#include <stdio.h> 
 
void main(){ 
  int a = 3; 
  int b = 4; 
 
  a = a ^ b;//使用异或交换 
  b = b ^ a; 
  a = a ^ b; 
 
  printf(\"%d, %d\\n\", a, b); 
 
  a = a - b;//使用加减交换 
  b = a + b; 
  a = b - a; 
 
  printf(\"%d, %d\\n\", a, b); 
 
  a ^= b ^= a ^= b; 
 
  printf(\"%d, %d\\n\", a, b); 
} 

#include <stdio.h> 
#include <stdlib.h> 
 
int sumof1(int x)//求一个数转换成二进制以后1的个数 
{ 
  int countx = 0; 
  while(x) 
  { 
    countx ++; 
    x &= x-1; //每位与一次x - 1；就能消掉最后一个1 
  } 
  return countx; 
} 
 
void main(){ 
 
  char c[10]; 
  int i = 999; 
 
  itoa(i, c, 10);//以10进制转换成字符数组 
  puts(c); 
 
  itoa(i, c, 16);//以16进制转换成字符数组 
  printf(\"0x%s\\n\", c); 
 
  itoa(i, c, 8);//以8进制转换成字符数组 
  printf(\"0%s\\n\", c); 
 
  itoa(i, c, 2);//以2进制转换成字符数组 
  puts(c); 
 
  i = atoi(c);//再将字符串转成整形 
  printf(\"%d\\n\", i); 
 
  printf(\"%d\\n\", sumof1(i));//以2进制表示时1的个数 
}