本文实例讲述了Android发送xml数据给服务器的方法。分享给大家供大家参考。具体如下:
一、发送xml数据:
public static void main(String[] args) throws Exception { String xml = \"<?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?><videos><video><title>中国</title></video></videos>\"; String path = http://localhost:8083/videoweb/video/manage.do?method=getXML ; byte[] entity = xml.getBytes(\"UTF-8\"); HttpURLConnection conn = (HttpURLConnection) new URL(path).openConnection(); conn.setConnectTimeout(5000); conn.setRequestMethod(\"POST\"); conn.setDoOutput(true); //指定发送的内容类型为xml conn.setRequestProperty(\"Content-Type\", \"text/xml; charset=UTF-8\"); conn.setRequestProperty(\"Content-Length\", String.valueOf(entity.length)); OutputStream outStream = conn.getOutputStream(); outStream.write(entity); if(conn.getResponseCode() == 200){ System.out.println(\"发送成功\"); }else{ System.out.println(\"发送失败\"); } }
二、接受xml数据:
public ActionForward getXML(ActionMapping mapping, ActionForm form, HttpServletRequest request, HttpServletResponse response) throws Exception { InputStream inStream = request.getInputStream(); byte[] data = StreamTool.read(inStream); String xml = new String(data, \"UTF-8\"); System.out.println(xml); return mapping.findForward(\"result\"); }
希望本文所述对大家的Android程序设计有所帮助。
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