本文实例为大家分享了C++计算每个字符出现的次数的实现代码,供大家参考,具体内容如下
#include <iostream> //#include <cstdlib> #include <ctime> using namespace std; const int NUMBER_OF_LETTERS = 26; const int NUMBER_OF_RANDOM_LETTERS = 100; void createArray(char []); void displayArray(const char []); void countLetters(const char [], int []); void displayCounts(const int []); int main() { char chars[NUMBER_OF_RANDOM_LETTERS]; createArray(chars); cout << \"The lowercase letters are:\" << endl; displayArray(chars); int counts[NUMBER_OF_LETTERS]; countLetters(chars, counts); cout << \"\\nThe occurrences of each letter are:\" << endl; displayCounts(counts); return 0; } void createArray(char chars[]) { srand((unsigned int)time(0)); for (int i = 0; i < NUMBER_OF_RANDOM_LETTERS; i++) { chars[i] = static_cast<char>(\'a\' + rand() % (\'z\' - \'a\' + 1)); } } void displayArray(const char chars[]) { for (int i = 0; i < NUMBER_OF_RANDOM_LETTERS; i++) { if ((i + 1) % 20 == 0) cout << chars[i] << \" \" << endl; else cout << chars[i] << \" \"; } } void countLetters(const char chars[], int counts[]) { for (int i = 0; i < NUMBER_OF_LETTERS; i++) counts[i] = 0; for (int i = 0; i < NUMBER_OF_RANDOM_LETTERS; i++) counts[chars[i] - \'a\']++; //经典 } void displayCounts(const int counts[]) { for (int i = 0; i < NUMBER_OF_LETTERS; i++) { if ((i + 1) % 10 == 0) cout << counts[i] << \" \" << static_cast<char>(i + \'a\') << endl; else cout << counts[i] << \" \" << static_cast<char>(i + \'a\') << \" \"; } cout << endl; }
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