Sql学习第一天——SQL 练习题(建表/sql语句)

前端技术 2023/09/06 MSSQL

题目:来自Madrid且订单数少于3的消费者  

建表:

复制代码 代码如下:

set nocount on --当 SET NOCOUNT 为 ON 时，不返回计数（表示受 Transact-SQL 语句影响的行数）。当 SET NOCOUNT 为 OFF 时，返回计数
use SY
GO
if object_Id(\'dbo.Orders\') is not null
drop table dbo.Orders
GO
if object_Id(\'dbo.Customers\') is not null
drop table dbo.Customers
GO
create table dbo.Customers
(
customerid char(5) not null primary key ,
city varchar(10) not null
);
insert into dbo.Customers values(\'FISSA\',\'Madrid\');
insert into dbo.Customers values(\'FRNDO\',\'Madrid\');
insert into dbo.Customers values(\'KRLOS\',\'Madrid\');
insert into dbo.Customers values(\'MRPHS\',\'Zion\');

create table dbo.Orders
(
orderid int not null primary key ,
customerid char(5) null references customers(customerid)
)
insert into dbo.Orders values(1,\'FRNDO\');
insert into dbo.Orders values(2,\'FRNDO\');
insert into dbo.Orders values(3,\'KRLOS\');
insert into dbo.Orders values(4,\'KRLOS\');
insert into dbo.Orders values(5,\'KRLOS\');
insert into dbo.Orders values(6,\'MRPHS\');
insert into dbo.Orders values(7,null);

------------------------------------------------------------------------------------------------------------------------------

做题分析：

复制代码 代码如下:

select customerid as 消费者,count(customerid) as 订单数
from dbo.Orders
where customerid in (
select customerid
from dbo.Customers
where city = \'Madrid\')
group by customerid
having count(customerid) < 3

结果如图所示：

--第一次想到的答案,突然发现少了一个来自Madrid的FISSA订单,FISSA订单数量为0,所以在Orders表中没有出现,所以上面的写法会少一个.

--推翻了上面的答案,又想到了用表的连接,而用内连接出现的情况会和上面的一样,所以我选择了左连接,如下:

复制代码 代码如下:

select C.customerid as 消费者,count(O.customerid) as 订单数
from dbo.Customers as C left join dbo.Orders as O on C.customerid = O.customerid
where C.city= \'Madrid\'
group by C.customerid
having count(C.customerid) < 3

结果如图所示：

--查询发现是正确的。

--分析查看不带条件的左连接

复制代码 代码如下:

select * from dbo.Customers as C left join dbo.Orders as O on C.customerid = O.customerid
复制代码 代码如下:

select * from dbo.Customers as C left join dbo.Orders as O on C.customerid = O.customerid

结果如图所示：

--书中给的标准答案是：

复制代码 代码如下:

select C.customerid , count(O.orderid) as numorders
from dbo.Customers as C left join dbo.Orders as O on C.customerid = O.customerid
where C.city= \'Madrid\'
group by C.customerid
having count(O.orderid) < 3
order by numorders

结果如图所示：

--书中给的只是多了一个order by 进行定义了排序方式(以numorders这一列的升序进行排序)

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